Sidney P. answered • 05/18/21
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From the ideal gas law, n = PV / RT = (760 mmHg) (1.0 L) /[(62.36 L mmHg/mol K) (273 K)] = 0.0446 mole.
Jaccari S.
asked • 05/17/21How many moles of nitrogen oxide are in a bag at 760 mmHg, 273 K, and has a volume of 1.0 liter?
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