Raymond B. answered 05/17/21
Math, microeconomics or criminal justice
11 possible outcomes
sums of
2,3,4,5,6,7, 8, 9, 10, 11, 12
only 1 way to get 2, 1 and 1
2 ways to get 3, 1 and 2, or 2 and 1
3 ways to get 4, 1 and 3, 3 and 1 or 2 and 2
4 ways to get 5
5 ways to get 6
6 ways to get 7
5 ways to get 8
4 ways to get 9
3 ways to get 10
2 ways to get 11
1 way to get 12
that sums up to 36 different ways to get 2 through 12
4+3+2+1 =10 ways to get 5 or less out of 36
Pr(5 or less)= 10/36 = 5/18
Pr(more than 5) = 1-5/18 = 13/18
Pr(even outcome) = 1+3+5+5+3+1 all over 36 = 18/36 = 1/2
that's the ways to get 2,4,6,8,10 or 12 over 36