Raymond B. answered 05/16/21
Math, microeconomics or criminal justice
P(b) = (x) = -x^2 -6x + 8 = profits
maximum profit = 8, with x=0, as any other non-negative output level gives less profit
take the derivative and set = 0
P'(b) =-2x -6 = 0
x =6/2= -3
max profit = -(-3)^2 -6(-3) + 8 = -9+18+8= 17 with negative output of -3
but that seems to have no real counterpart in business other than possibly buying up 3 million to cut back on production available to the public, such as when OPEC cut back on oil to drive up prices. Similar to the recent oil shortage caused by a Russian hacker that sent gas prices over $3 per gallon and up to $9 in some places.
-x^2 -6x + 8
= -(x^2 +6x - 8)
= -(x^2 +6x + 9) +8+9
=-(x+3)^2+ 17 which has vertex (-3,17) which is a profit maximizing point with output = x = -3 and profit=17
with a negative coefficient of the x^2 term, the vertex is a maximum point of a downward opening parabola.
Possibly you hit the - sign when you meant =? the keyboard keys are close together. if so, then
P(x) =x^2 -6x + 8 and
P'(x) =2x-6x =0
x =6/2 = 3 = profit minimizing output level with P=9-18+8 = 1. Maximum profit would be an infinite output level.
x^2 -6x + 8
= (x^2-6x + 9) +8 -9
=(x-3)^2 -1
vertex is (3,1) a minimum profit level of $1 million at output of 3 million