help please

Question

Solve the equation for the requested variables.

p(k u+z)=n+c

Solve for p: p=

Solve for u: u=

(entry tip: if you have several parts to a numerator or denominator, put them in parenthesis. to type (2x)/(a+b) we type "(2x)/(a+b)" )

Answer 1

     p(ku + z) = n + c

Since p is being multiplied by all the term inside the parentheses, you solve for p by dividing both sides of the equation by the terms inside the parenthesis. That is, divide both sides by ku + z:

     p(ku + z) = n + c

     p(ku + z)/(ku + z) = (n + c)/(ku + z)

     p = (n + c)/(ku + z)

To solve for u, first distribute the p by multiplying it by each term inside the parenthesis:

     p(ku + z) = n + c

     pku + pz = n + c

Then, subtract pz from both sides of the equation:

     pku + pz - pz = n + c - pz

     pku = n + c - pz

Now divide both sides by pk to solve for u:

     pku = n + c - pz

     pku/(pk) = (n + c - pz)/(pk)

     u = (n + c - pz)/(pk)