If a balloon containing 1000L of gas at 50oC and 101kPa rises to an altitude where the pressure is 50.5kPa and the temperature is 10oC, the volume of the balloon at the new conditions would be:

Question

570

400

1752

2500

Answer 1

Step 1 (find moles in first part):

1. I converted kPa to atm
2. I converted celsius to kelvin
3. I used gas constant for R

PV = nRT

(0.996792)(1000) = n (0.08206)(323.15)

996.792 = 26.517689n

996.792 / 26.517689 = n

37.58970097 = n

Step 2 (use moles to find new volume):

PV = nRT

(0.4983962)(V) = (37.58970097)(0.08206)(283.15)

(0.4983962)(V) = 873.4075655

V = 873.4075655 / 0.4983962

V = 1752.436245 L

Answer:

(c) 1752

Answer 2

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