Paul D. answered 05/12/21
PhD in Mathematics - Specializing in AP Calculus
Solution:
Set up the vertical y-axis pointing upward so that the origin is at the center of aquarium. Let g = 9.8 m/s^2 and ρ = 1000 kg/m^3. For any y between 0 and 1/2, pick a typical slice Δy. Then the work done for this typical slice is
ΔW ≈ Weight * Height
= ρg*(3*1*Δy) * (1/2 - y)
So dW = 3ρg(1/2 - y) dy
Therefore, the work required is
W = int_0^(1/2) 3ρg(1/2 - y) dy
= 3ρg*(1/2 y -1/2 y^2) |_0^(1/2)
= 3/8 ρg
= 3/8 * 1000* 9.8
= 3675
Answer: The work needed to pump half of the water out of the aquarium is 3675 joules.