Todd W. answered 05/12/21
Recent College Graduate Specializing Biology Tutoring
28.9g NO x (1 mol NO / 30.01g NO) = 0.963 mol NO
0.963 mol NO x (1 mol O2 / 1 mol NO) = 0.963 mol O2
0.963 mol O2 x (31.98g O2 / 1 mol O2) = 30.8g O2
Answer: 38 grams of oxygen gas are required for the complete reaction of 28.9 grams of nitrogen monoxide.
*Let me know if there is anything you do not understand here and I can give you a more in-depth explanation.