What is the difference in volume between A) 2.591 g of carbon monoxide at 465 K and B) the same mass of carbon dioxide at 301 K if they are both at 94.2 kPa? Answer needs to be rounded to 3 sig figs.

Question

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Answer 1

From ideal gas law, V = nRT/P. Number of moles: (2.591g CO) * (1 mol CO /28.01g CO) = 0.09250 mole CO.

A) V = (0.09250 mol) (8.314 L kPa/mol K) (465 K) / (94.2 kPa) = 3.796 L.

B) Substitute 301 K for 465 in the above, yielding V = 2.457 L. The volume difference is 1.34 L to 3 sig figs.