How many grams of HBO2 are produced from 5.32 moles of B2H6

Answer 1

Apparently the reaction is B₂H₆ + 2 O₂ --> 2 HBO₂ + 2 H₂. So first use the mole ratios from the balanced reaction to convert: (5.32 mol B₂H₆) * (2 mol HBO₂ /1 mol B₂H₆) = 10.64 moles of HBO₂, then multiply by molar mass: (10.64 mol HBO₂) * (43.81 g HBO₂ /1 mol HBO₂) = 466 g HBO₂.