A 0.5-m high toddler is playing 10 m in front of a convex mirror with radius of curvature of 7 m. What is the location of his image? What is the height of his image?

Answer 1

f= - 1/2*radius of curvature = -3.5m

do=10

ho=.5m

1/di+1/do=1/f ... di= 2.59 m ... virtual image behind mirror

hi/ho=M=di/do ... hi=.259*.5=1.3m