Determine the net change and the average rate of change for the function f(t) = t ^ 2 - 5t between t = 3 and t = 3 + h

Answer 1

t₁=3 t₂=(3+h)

net change =f(3+h) -f(t)=[(3+h)²-5(3+h)] - [3² -5*3]=h² +h

average change=net change/(t₂-t₁) =(h² +h)/h=h+1