What pressure is exerted by 1.43 mol of hydrogen gas in a 3.53 L container at 16◦C? Answer in units of atm.

Question

What pressure is exerted by 1.43 mol of hydrogen gas in a 3.53 L container at 16◦C? Answer in units of atm.

Answer 1

We can use the ideal gas law to calculate the pressure of hydrogen gas under these conditions. The ideal gas law is written as PV = nRT where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant (0.0821 L^.atm/mol^.K), and T is the temperature. Because of the units of R, the temperature must be expressed in Kelvin so add 273 to the given temperature, 16^OC + 273 = 289 K.

PV = nRT

P = (nRT)/V

P = (1.43 mol x 0.0821 L^.atm/mol^.K x 289 K)/3.53 L

P = 9.61 atm