Sidney P. answered 05/10/21
Astronomy, Physics, Chemistry, and Math Tutor
Use the ideal gas law PV = nRT, yielding per hour, V = nRT/P = (50 mol/hr) (62.36 L torr/mole K) (35 + 273K) / (740 torr) = 1298 L/hr. In 6 hours we would have 7800 L of CO [to 2 sig figs].