Calculate the amount of iron (III) sulfate produced from 15.0 grams of iron. Please just answer with the number, do not include the units. *

Question

Calculate the amount of iron (III) sulfate produced from 15.0 grams of iron. Please just answer with the number, do not include the units. *

Answer 1

I'll assume the iron is reacted with sulfuric acid in order to show the mole ratio for Fe₂(SO₄)₃ vs Fe: 2 Fe + 3 H₂SO₄ --> Fe₂(SO₄)₃ + 3 H₂. Convert grams to moles, modify via mole ratio, and convert moles of product to grams: (15.0g Fe) * (1 mol Fe / 55.845g Fe) * (1 mol Fe₂(SO₄)₃ / 2 mol Fe) * (399.86g Fe₂(SO₄)₃ / 1 mol Fe₂(SO₄)₃) = 53.7 [g Fe₂(SO₄)₃]

Answer 2

https://youtu.be/45mKzpJ5iIg