Anjela R.
asked 05/09/21is it A or ????
Calculate the mass of carbon dioxide produced from 15.3 g of octane in the reaction below.
2C8H18 + 25O2 → 16CO2 + 18H2O
a.53.1 g carbon dioxide
b.0.737 g carbon dioxide
c.47.2 g carbon dioxide
d.94 g carbon dioxide
e.1.072 g carbon dioxide
2 Answers By Expert Tutors
Hello, Anjela,
I note in the comments that you concluded it wasn't option A. That was good to see, but the comment was cut short, so it wasn't clear if you had picked an answer.
Note that the balanced equation says we'll obtain an amount of CO2 equal to 8 times the amount of C8H18 from the reactant side. 15.3 grams of octance is (15.3 grams/114.1 grams/mole) = 0.134 moles of octance. 8 times that amount yields 1.073 moles of CO2. Convert moles CO2 into grams CO2 by multiplying by the molar mass of CO2 (1.073g*44g/mole) = 44.6 grams.
This isn't an option in the question, so I may have made a math error somewhere. But the logic should work.
Bob
Anjela R.
yes, this is isn't an option i got c 47.2 g carbon dioxide. But Thank you !!!05/10/21

Paolo S. answered 05/09/21
PhD student with 5+ years of Tutoring and Teaching Chemistry Labs
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Anjela R.
never mind i see what i did wrong its not a05/09/21