If there are 7.6 x 1011 mg of sulfur dioxide gas at STP, how many milliliters does this occupy? Give your answer in scientific notation

Question

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Answer 1

mg to g

( 7.6 x 10¹¹ mg) × (1g/1000 mg)= 7.6 x 10⁸ g SO2(g)

g to mol

7.6 x 10⁸ g SO₂ × (1mol SO₂ / 64.058 g SO₂)=1.19×10⁷ mol SO₂

mol to L with standard molar volume

1.19×10⁷ mol SO₂ ×(22.4 L / 1 mol)=2.66×10⁸L

L to mL

2.66×10⁸L ×(1000mL / 1L)=2.66×10¹¹ mL