If 2.47 moles of calcium chloride reacts with fluorine gas, how many grams of calcium fluoride are made?

Question

Need help with this question

Answer 1

Hello, Tyler,

We need a balanced equation. Write down the chemical formaulas and find a way to balanced the elements on both sides.

I think this is balanced;

CaCl₂ + 2F = CaF₂ + Cl₂

If this looks balanced to you, we can see that 1 mole of calcium chloride will produce 1 mole of calcium fluoride, a 1:1 molar ratio. This assumes we have sufficient fluorine available.

Since we start with 2.47 moles of CaCl₂, we would predict we'd get the same amount, 2.47 moles of CaF₂.

Multiply 2.47 moles of CaF₂ by the molar mass of CaF₂:

(2.47 moles CaF₂)*(78.1 grams CaF₂/mole CaF₂)

That amounts to 193 grams CaF₂ to 3 sig fig.

Bob

Answer 2

Balanced reaction: CaCl₂ + F₂ --> CaF₂ + Cl₂. Then (2.47 mol CaCl₂) * (1 mol CaF₂ / 1 mol CaCl₂) * (78.07g CaF₂ / 1 mol CaF₂) = 193g CaF₂.