If 5.78 moles of calcium nitrite reacts with excess cesium, how many moles of cesium nitrite can be made

Question

No clue, how to work this out.

Answer 1

First, balance the reaction to have the correct mole ratio to use: Ca(NO₂)₂ + 2 Cs --> 2 CsNO₂ + Ca. So (5.78 mol Ca(NO₂)₂) * (2 mol CsNO₂ / 1 mol Ca(NO₂)₂) = 11.56 mol CsNO₂.