stiochiometry: chemistry

Question

1 C₅H₁₂ + 8 O₂ --> 5 CO₂ + 6 H₂O

Starting with 83.42 grams of Oxygen gas in excess C₅H₁₂, how much Carbon Dioxide can be created?

Answer 1

I believe this is a theoretical yield problem, so you have to convert the oxygen to moles and then convert moles of oxygen into moles of carbon dioxide. I was not sure if you needed moles or grams for the answer, so I did both (in bold).

83.42 g O₂ x (1 mol / 31.99g) = 2.61g O₂

2.61 g O₂ x (5 mol CO₂ / 8 mol O₂) = 1.63 mol CO₂

1.63 mol CO₂ x (44.01g / 1 mol) = 71.74g CO₂