A gas occupies 0.9 L at a temperature of 27.0 °C. What is the volume at 132.0 °C?

Answer 1

Apparently this is at constant pressure, else it can't be solved. From the ideal gas law when amount of gas n and P are constant, V₂ / V₁ = T₂ / T₁ so V₂ = (0.9 L) (132.0 +273.15K) / (27.0 +273.15 K) = 1.21L.