What would the mass be, in grams, of 843 liters of carbon dioxide (CO2) measured at STP

Answer 1

First, remember that at Standard Temperature and Pressure (STP), 1 mole of any gas will occupy a volume of 22.4 L. So, to start this problem we would first convert 843 L of carbon dioxide to moles and then convert the moles to grams using the molar mass of carbon dioxide, which is 44.01 g/mol.

843 L CO₂ x (1 mol / 22.4 L) = 37.63 mol CO₂

37.63 mol CO₂ x (44.01 g CO₂ / 1 mol CO₂) = 1656.1 g CO₂