Sn + HF SnF2 + H2 How many grams of SnF2 are produced from the reaction of 30.00g HF with Sn? Answer; grams

Answer 1

The balanced chemical equation for the reaction is: Sn + 2HF → SnF₂ + H₂

We can interconvert between moles of each specie by using the molar ratio of each. The molar ratio is the coefficient in front of specie in the balanced chemical equation.

30 g HF * (1 mol HF / 20 g HF) * ( 1 mol SnF₂ / 2 mol HF) * ( 156.71 g SnF₂ / 1 mol SnF₂) = 117.5 g SnF₂

Explanation: The first step is to convert grams of HF into moles of HF by dividing by its molar mass. Then, we are in moles of HF because units along the diagonal cancel, and we can use the molar ratio to convert between moles of HF to moles of SnF_2. Then, we are in moles of SnF₂ and we can convert to grams of SnF₂ by multiplying by its molar mass.