How many liters do 54.4 grams of ammonia gas occupy at STP?

Question

I don't quite understand what to do here.

Answer 1

Hi Tyler!

For this one we are utilizing the fact that 1 mole of any gas occupies 22.4 L at STP.

So to begin this problem: we need to have moles of ammonia...so we need to convert the grams to moles using the molar mass (Mr)

54.4 grams NH₃ x 1 mol NH_{3 =} 3.194 moles of NH₃

17.031 g

Then use that relationship above to change moles of ammonia to a volume:

3.194 moles NH₃ x 22.4 L = 71.55 L NH₃

1 mol