
Michael M. answered 05/05/21
Math, Chem, Physics, Tutoring with Michael ("800" SAT math)
Assume that all the phosphorus is used in the reaction (85g)
Find how much O2 reacts with it.
85g P x (1mol P/ 123.88g) x (5mol O2/ 4mol P) x (32g O2/ 1 mol O2) = 27.446g O2.
Therefore the phosphorus will run out and only 27.446 grams of oxygen (out of the 80g O2) will react.
The phosphorus is the limiting reactant and the oxygen is the excess.
Use the limiting reactant (85g of phosphorus) and find how much P2O5 can be made
I'm assuming they want this in grams.