How many mililiters of 0.291 M KOH are needed to titrate 15.82 mL of 0.175 M H2SO4?

Question

Need to show work on how you got the answer (BCA table?). This is 11th grade chemistry.

Answer 1

At the equivalence point the moles of KOH will be the same as the moles of Sulfuric acid. So we calculate the moles to be M*V= 0.175M*0.01582 L= 2.77*10^-3 moles of H₂SO₄. 1 mole of Sulfuric acid will contain twice as many H⁺. So, the concentration of KOH will be 2*moles of KOH/M=2.77*10^-3 /0.291 M = 19 mL. Even simpler, you can use 2M1V1=M2V2. Rearrange for V2 and you get the same answer, without changing the units for mL.