At the equivalence point the moles of KOH will be the same as the moles of Sulfuric acid. So we calculate the moles to be M*V= 0.175M*0.01582 L= 2.77*10-3 moles of H2SO4. 1 mole of Sulfuric acid will contain twice as many H+. So, the concentration of KOH will be 2*moles of KOH/M=2.77*10-3 /0.291 M = 19 mL. Even simpler, you can use 2M1V1=M2V2. Rearrange for V2 and you get the same answer, without changing the units for mL.