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Question

Determine the mass of aluminum (Al) produced in the reaction if 30.00 grams of magnesium (Mg) was consumed. 2AlPO4 (aq) + 3Mg (s) ⟶ 2Al (s) + 1Mg3(PO4)2 (aq)

Answer 1

(30.00g Mg) * (1 mol Mg / 24.305g Mg) * (2 mol Al / 3 mol Mg) * (26.982g Al / 1 mol Al) = 22.20g Al.