Calculate the number of moles of oxygen gas (O2) needed to fully react with 9.75x1023 molecules of ethane (C2H6). 2C2H6 (g) + 7O2 (g) ⟶ 4CO2 (g) + 6H2O (g)

Answer 1

Using Avogadro's number and mole ratio from balanced reaction,

(9.75 x 10²³ C₂H₆ molecules) * (1 mol C₂H₆ / 6.022 x 10²³ molecules) * (7 mol O₂ / 2 mol C₂H₆) = 5.67 moles of O₂.