Jonathan H. answered 05/02/21
3+ years Chemistry Teaching Experience
The first thing necessary to do is to calculate the molar mass of Ca3(PO4)2 to find to number of moles used in the reaction.
- [3(40.08) + 2(30.9738+63.9976)] = 310.1828 g/mol
- Then, 100g/ 310.1828g/mol = 0.3223905387 moles Ca3(PO4)2 used in the reaction.
- Finally, use the stoichiometric ratio between Ca3(PO4)2 and P4 to calculate moles of P4
- (0.3223905387 moles Ca3(PO4)2 ) (1/2) = 0.1611952694 moles P4 created.
- ANSWER: 0.1612 moles