How many grams of Copper Hydroxide will be produced?

Question

If 3.00 grams of copper(II)nitrate reacts with 4.35 grams of sodium hydroxide, how many grams of copper(II)hydroxide would be produced?

1. a. 0.783grams
2. b. 1.56grams
3. c. 1.38grams

Answer 1

1) Write the balanced chemical reaction.

Cu(NO₃)₂ (aq) + 2 NaOH (aq) → Cu(OH)₂ (s) + 2 NaNO₃ (aq)

2) Convert g of each reactant to g of Cu(OH)₂. The reactant that produces the lesser amount of Cu(OH)₂ is the limiting reactant.

3.00 g Cu(NO₃)₂ x (1 mol Cu(NO₃)₂ / 187.56 g Cu(NO₃)₂ ) x (1 mol Cu(OH)₂ / 1 mol Cu(NO₃)₂) x (99.58 g Cu(OH)₂ / 1 mol Cu(OH)₂) = 1.59 g Cu(OH)₂

4.35 g NaOH x (1 mol NaOH / 40.00 g NaOH) x (1 mol Cu(OH)₂ / 2 mol NaOH) x (99.58 g Cu(OH)₂ / 1 mol Cu(OH)₂) = 5.41 g Cu(OH)₂

Since Cu(NO₃)₂ is the limiting reactant, it will be completely consumed in the reaction forming 1.59 g of Cu(OH)₂. Closest answer is b = 1.56 g!