Sidney P. answered 05/01/21
Astronomy, Physics, Chemistry, and Math Tutor
First, balance the reaction, then just use the mole ratio: 2 KClO3 --> 2 KCl + 3 O2.
(3.8 mol KClO3) * (3 mol O2 / 2 mol KClO3) = 5.7 moles.
Anjela R.
asked 04/30/21A 3.8-mol sample of KClO3 was decomposed according to the equation How many moles of O2 are formed assuming 100% yield?
a. 5.7 mol
b. 1.9 mol
c. 3.8 mol
d. 2.5 mol
e. 3.2 mol
Sidney P. answered 05/01/21
Astronomy, Physics, Chemistry, and Math Tutor
First, balance the reaction, then just use the mole ratio: 2 KClO3 --> 2 KCl + 3 O2.
(3.8 mol KClO3) * (3 mol O2 / 2 mol KClO3) = 5.7 moles.
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