Hello, Anjela,
Thanks for suggesting an answer. It isn't quite what I'm concluding, however, so I'd like to share my thought on how one can answer thr question. It is asking for the moles of O2 required to completely consume the ethene. We only need a balanced equation and the moles of ethene contained in 23.6 grams of the material.
Here's my balanced equation:
C2H4 + 3O2 = 2CO2 + 2H2O
If this is correct, it means that we need 3 moles O2 for every 1 mole of ethene. So if we can determine the moles of ethene, we would multiply that by 3 to find moles O2 required.
Moles C2H4
Divide the mass by the molar mass of 28.0. 23.6/28.0 = 0.842 moles ethene
Moles oxygen: multiply moles ethene by 3, equals 2.52 moles O2
I hope this helps,
Bob