If 3.50 moles of butane are burned according to the following balanced equation how many grams of carbon dioxide are formed. 2C4H10+13O2=>8CO2+10H2O

Answer 1

In this stoichiometry, first convert moles of the reactant to moles of product using the coefficients in the balanced reaction, then multiply by molar mass of the product. It's basically dimensional analysis.

(3.50 mol C₄H₁₀) * (8 mol CO₂ / 2 mol C₄H₁₀) * (44.0g CO₂ / 1 mol CO₂) = 616 mol CO₂.