Mean,Median and range (Help plss)

Question

This data set shows the ages of members of a singing group.

             22, 23, 16, 24, 20

Which of these numbers is NOT the mean, median, or range of the data?

A.8

B.20

C.21

D.22

Answer 1

Let's start by finding the value for the mean,medisn and range.

To find the mean you use the formula =(∑xi)/n

x̄=mean, ∑=the sum of x_i=the value of the x's, n=the number of items

to put it in simpler words you add the sample values together and then divide that number by the amount if values in the sample.

In the problem above x_i =22,23,16,24 and 20 so ∑x_i=105 because I added all those values together. n=5 because there are 5 values listed;22,23,16,24 and 20. We then divide 105/5 which is 21. So x̄/the mean is 21.

To find the median you need to line up the values in your problem from least to greatest. Then you find the middle number which is equal to your median. I like to rewrite the values on a paper and alternate between crossing off a number from the left side and then the right until only one number is left. (If there is an even amount of values than you take the two middle values and find the mean, meaning you add them together and then divide them by two). In our problem you would line up the numbers like the following; 16,20,22,23,24. When you cross out a value from each side alternating between the left and right you will be left with 22. Therefore the median here is 22.

To find the range you use the equation X=Max(x)-Min(x).

X=Range, Max(x)=the maximum or largest value from the sample Min(x)= the minimum or smallest value from sample.

Our largest value in this sample is 24 and the smallest is 16 so you would subtract 24-16 which is 8 so your X/range=8

now for the multiple choice:

Our mean is 21, our median is 22 and range is 8.The question asks which choice is not the mean,median or range so the answer must be B.20.