Need help, this is confusing

Question

If 50.6 g of O₂ is mixed with 50.6 g of H₂ and the mixture is ignited, what is the maximum mass of water that may be produced?

                         2H₂ + O₂ → 2H₂O

Answer   grams H₂O (Round your answer to the nearest tenth)

Answer 1

Find moles of H₂O that each produces: (50.6g O₂) * (1 mol O₂ / 32.0g O₂) * (2 mol H₂O / 1 mol O₂) = 3.16 mol H₂O.

(50.6g H₂) * (1 mol H₂ / 2.02g H₂) * (2 mol H₂O / 1 mol H₂) = 25.1 mol H₂O. So H₂ will be left over when the limiting O₂ is consumed. Maximum mass of water is (3.16 mol H₂O) * (18.02g H₂O / 1 mol H₂O) = 57.0g H₂O.