Ishwar S. answered 05/01/21
University Professor - General and Organic Chemistry
N2 (g) + O2 (g) → N2O5 (g)
Balance the oxygen atoms first. Since we have 2 oxygen atoms on the reactant side and 5 oxygen atoms on the product side (an even:odd combo), the common multiple between 2 and 5 is 10. Therefore, to balance the oxygen atoms, we need a coefficient of 5 on the reactant side and a coefficient of 2 on the product side.
N2 (g) + 5 O2 (g) → 2 N2O5 (g)
After balancing the oxygen atoms, the product side now has 4 nitrogen atoms and there are only 2 N atoms on the reactant side. To balance nitrogen, you need a coefficient of 2 on the reactant side.
2 N2 (g) + 5 O2 (g) → 2 N2O5 (g)
Always double check your work.
Nitrogen: 4 on reactant side and 4 on the product side
Oxygen: 10 on reactant side and 10 on the product side