The theoretical yield for the reaction is 0.281 g O₂. Given that the reaction has a percent yield of 83.4%, what is the mass in g of oxygen gas that is actually produced?

Question

4 KO₂ (s) + 2 CO₂(g) → 2 K₂CO₃(s) + 3 O₂(g)

Answer 1

Percent yield = 83.4 = 100 * actual/theoretical, 0.834 = actual/0.281g, actual = 0.234g O₂.