A container holding 4.50 moles of a gas has a volume of 5.00 L at 60° C. How much pressure is exerted within the container? R=0.08206 L atm/ mol K

Answer 1

Hi Jake W.,

Use PV = nRT. In this case P =nRT/V, with n=4.5, R=0.08026, T=273.15 + 60 = 333.15 K, and V=5.00.

P = 4.5*0.08026*333.15/5 = 2.39 atm.

I hope this helps, Joe.