If the initial temperature of an ideal gas at 2.250 atm is 62.00 ∘C, what final temperature would cause the pressure to be reduced to 1.700 atm? 𝑇=

Question

If the initial temperature of an ideal gas at 2.250 atm is 62.00 ∘C, what final temperature would cause the pressure to be reduced to 1.700 atm? 𝑇=

Answer 1

Apparently V is constant, so the ideal gas law reduces to P₂ / P₁ = T₂ / T₁ and T₂ = (62.00 + 273.15 K) * (1.700 atm) / (2.250 atm) = 253.2 K = -19.9 °C.