Sidney P. answered • 04/30/21
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Heat Q = m*c*ΔT, so ΔT = Q / m*c = (835.92 J) / [(120 g) * (0.129 J/g•°C)] = +54.0 °C.
Iva Y.
asked • 04/29/21835.92 J of energy are used on a 120g chunk of lead. What would the change in temperature be? (CLead = 0.129 J/g*C)
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