General Chemistry 1

Question

The combustion of octane, proceeds according to the reaction shown.

2C8H18 (I) + 25O2 (g) →  16CO2 (g) + 18H2O (I)

If 346 mol of octane combusts, what volume of carbon dioxide is produced at  10 degrees celcius and 0.995 atm? 

Answer:

V=_________L

Answer 1

Hello, Madison,

346 moles of octane combusted according to the balanced equation

2C8H18 (I) + 25O2 (g) →  16CO2 (g) + 18H2O (I)

would produce (16 moles CO₂/2 moles octane)*(346 moles octane)= 2768 moles CO₂. Stand back.

Use the ideal gas law with R=0.082058 L*atm*K^-1mole^-1. Convert 10^oC to ^oK by adding 273.15. Enter the data into PV=nRT and solve for V.

I get 64,636 liters, rounded to 64.6 kL.

Bob