Sidney P. answered 04/29/21
Astronomy, Physics, Chemistry, and Math Tutor
The work done is pressure times volume change, W = P ΔV, where P must be in units of Pascals and volume in cubic meters. P = 783 torr * (1.013 x 105 Pa / 760 torr) = 1.044 x 105 Pa. ΔV = W/P = (134.9 J) / (1.044 x 105 Pa) = 1.293 x 10-3 m3 = 1.293 L = 1,293 mL. So new volume is 69.9 mL + 1,293 mL = 1,362 mL.