Potassium Chlorate is heated in a test tube producing potassium chloride and oxygen gas. How many moles of oxygen gas would be generated from 3.85 grams of potassium chlorite?

Question

Balanced Equation: 2 KClO3 (s) ->2 KCl (s) + O2 (g)

Answer 1

First a correction to the reaction: put a "3" in front of O₂. Then (3.85g KClO₃) * (1 mol KClO₃ / 122.5g KClO₃) * (3 mol O₂ / 2 mol KClO₃) = 0.0471 mol O₂ gas.