Sidney P. answered 04/29/21
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The balanced reaction: 2 Al + 6 HCl --> 2 Al Cl3 + 3 H2.
(54.5g Al) * (1 mol Al / 27.0g Al) * (3 mol H2 / 2 mol Al) * (22.4 L / 1 mol gas at STP) = 67.8 L H2 gas.