If the pressure of a 2.3 mole sample of gas is initially 1.5 atm, the volume is 1.0 L and the temperature is 25ºC

Question

1. what would the new volume be if 1.1 moles are added and the pressure is changed to 6.0 atm and 100.0ºC?

Answer 1

From the ideal gas law, P₂V₂ /P₁V₁ = n₂T₂ /n₁T₁ which in this case rearranges to V₂ = n₂T₂P₁V₁ /n₁T₁P₂ = (3.4 mol)(100 +273K)(1.5 atm)(1.0 L) / [(2.3 mol)(25 +273K)(6.0 atm)] = 0.46 L.