A reaction has a standard free‑energy change of −17.50 kJ mol−1(−4.183 kcal mol−1)

Question

Calculate the equilibrium constant for the reaction at 25 °C.

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Answer 1

You will have to use the relation ΔG^o = -RTlnK and solve for K. You must use the correct value for R which is in this case is 8.315 j K^-1mol^-1.

lnK = ΔG^o/ -RT = -17.5 x 10³ jmole^-1 / (-8.315 j K^-1mol^-1 x 298 °K) = 7.06

Take antilog of 7.06, K = 1164