Count E's. Read in a string, print out the number of e's in it.

Question

Read in a string, print out the number of e's in it. Note that the string may have spaces in it. A call to getline looks like getline(cin, myVariable) where myVariable is a string variable that will be set to hold the contents of the line.

Samples:

Input: Jane Doe Output: 2

Input: why Output: 0

Hints:

1. there is no magic "count things" function
2. A good first step would be to print out all the characters one at a time. Then maybe modify your code to only print when you see an 'e'. Then worry about counting them.

Code:

#include <iostream>

using namespace std;

int main()

{

//YOUR_CODE

}

Answer 1

using namespace std;

#include <iostream>

#include <string>

int main()

{

string inbuff;

cout << "Input :>";

getline(cin,inbuff);

int strLen = inbuff.length();

int eCount=0;

for (int iLoop=0; iLoop<strLen; iLoop++)

{

char ch = inbuff[iLoop];

if (ch=='e' || ch=='E')

{

eCount++;

}

}

cout << "The letter E appears >" << eCount << " times in the string >"<< inbuff << "<" << endl;

}