How do you set up an ice table given 8.0 mL of 0.10 M HC2H3O2 is titrated with 0.10 M NaOH

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How do you set up an ice table given 8.0 mL of 0.10 M HC2H3O2 is titrated with 0.10 M NaOH

K_a = [H₃O⁺][C₂H₃O^2-]/[HC₂H₃O₂]

Answer 1

Hello, Sdasd,

I had posted a more detailed analysis of this ICE table, but it hasn't appeared yet. Here is the table, minus the detailed explanation. The initial concentrations of 0.05M are due to the mixing of the two reagents, with 8 ml of 0.10 M NaOH as the required amount to react with the acetic acid reactant. I'll leave it at that and hope the longer post appears at some point.

Bob