What is the percent by volume of ethanol in a solution that contains 50. mL of ethanol dissolved in 121 mL of water?

Answer 1

To find % by volume use the equation:

%volume = [(volume of solute)/(volume total solution)] x 100

In this case we plug in the given volumes into the equation and solve. Be sure to add the volume of ethanol to the total solution volume (50mL + 121mL = 171mL total volume):

(50 mL/171 mL) x 100 = 29.2% ethanol