How many grams of aluminum can be heated from 90oC to 120oC if 2090 joules are applied? The specific heat of aluminum is 0.88 J/goC.

Answer 1

q = m c ΔT

q = 2090 J

m = ? g

c = 0.88 J/g °C

T_f = 120 °C

T_i = 90 °C

ΔT = T_f - T_i = 120 - 90 = 30 °C

Plug in the numbers in the above equation, you get

2090 = m x 0.88 x 30

2090 = 26.4m

m = 2090 / 26.4 = 79 g