154 grams of antifreeze absorbs 504 Joules of energy in going from 21°C to 35°C. what is the specific heat of the antifreeze?

Question

154 grams of antifreeze absorbs 504 Joules of energy in going from 21°C to 35°C. what is the specific heat of the antifreeze? Show your work and round your answer to the hundredths place. 

Answer 1

q = m c ΔT

q = 504 J

m = 154 g

c = ? J/g °C

T_f = 35 °C

T_i = 21 °C

ΔT = T_f - T_i = 35 - 21 = 14 °C

Plug in the numbers in the above equation, you get

504 = 154 x c x 14

504 = 2156c

c = 504 / 2156 = 0.23 J/g°C